Dr. Helmenstine holds a Ph.D. in biomedical sciences and is a science writer, educator, and consultant. She has taught science courses at the high school, college, and graduate levels.
Updated on August 02, 2022The empirical formula of a compound is defined as the formula that shows the ratio of elements present in the compound, but not the actual numbers of atoms found in the molecule. The ratios are denoted by subscripts next to the element symbols.
Also Known As: The empirical formula is also known as the simplest formula because the subscripts are the smallest whole numbers that indicate the ratio of elements.
Glucose has a molecular formula of C6H12O6. It contains 2 moles of hydrogen for every mole of carbon and oxygen. The empirical formula for glucose is CH2O.
The molecular formula of ribose is C5H10O5, which can be reduced to the empirical formula CH2O.
Sometimes determining the whole number ratio is tricky and you'll need to use trial and error to get the correct value. For values close to x.5, you'll multiply each value by the same factor to obtain the smallest whole number multiple. For example, if you get 1.5 for a solution, multiply each number in the problem by 2 to make the 1.5 into 3. If you get a value of 1.25, multiply each value by 4 to turn the 1.25 into 5.
You can use the empirical formula to find the molecular formula if you know the molar mass of the compound. To do this, calculate the empirical formula mass and then divide the compound molar mass by the empirical formula mass. This gives you the ratio between the molecular and empirical formulas. Multiply all of the subscripts in the empirical formula by this ratio to get the subscripts for the molecular formula.
A compound is analyzed and calculated to consist of 13.5 g Ca, 10.8 g O, and 0.675 g H. Find the empirical formula of the compound.
Start by converting the mass of each element into moles by looking up the atomic numbers from the periodic table. The atomic masses of the elements are 40.1 g/mol for Ca, 16.0 g/mol for O, and 1.01 g/mol for H.
13.5 g Ca x (1 mol Ca / 40.1 g Ca) = 0.337 mol Ca
10.8 g O x (1 mol O / 16.0 g O) = 0.675 mol O
0.675 g H x (1 mol H / 1.01 g H) = 0.668 mol H
Next, divide each mole amount by the smallest number or moles (which is 0.337 for calcium) and round to the nearest whole number:
0.337 mol Ca / 0.337 = 1.00 mol Ca
0.675 mol O / 0.337 = 2.00 mol O
0.668 mol H / 0.337 = 1.98 mol H which rounds up to 2.00
Now you have the subscripts for the atoms in the empirical formula:
Finally, apply the rules of writing formulas to present the formula correctly. The cation of the compound is written first, followed by the anion. The empirical formula is properly written as Ca(OH)2
Cite this Article Your CitationHelmenstine, Anne Marie, Ph.D. "Empirical Formula: Definition and Examples." ThoughtCo, Apr. 5, 2023, thoughtco.com/definition-of-empirical-formula-605084. Helmenstine, Anne Marie, Ph.D. (2023, April 5). Empirical Formula: Definition and Examples. Retrieved from https://www.thoughtco.com/definition-of-empirical-formula-605084 Helmenstine, Anne Marie, Ph.D. "Empirical Formula: Definition and Examples." ThoughtCo. https://www.thoughtco.com/definition-of-empirical-formula-605084 (accessed September 11, 2024).
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